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If tan2A = cot(A – 18°) where 2A is an acute angle. Find the value of A.
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Tan 2A = cot(A – 18°)
According to identify ( Tan Theta = Cot (90- Theta)
Cot (90 -2 A ) = Cot ( A-18)
90-2A = A-18
-2A-A = -18-90
-3A = -108
A= 108/3
A= 36°
thanks me Later ❤️
According to identify ( Tan Theta = Cot (90- Theta)
Cot (90 -2 A ) = Cot ( A-18)
90-2A = A-18
-2A-A = -18-90
-3A = -108
A= 108/3
A= 36°
thanks me Later ❤️
sakkuu00:
right ans
Answered by
1
Answer:
Step-by-step explanation:
tan2A=cot(A-18)
cot(90-2A)=cot(A-18) { tanQ=cot(90-Q)}
90-2A=A-18
90+18=A+2A
108=3A
108/3=A
36=A
or A=36
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