Question

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Answer 1

Given  :

sec θ + tan θ = l ...........( 1 )

We know that :

sec² θ - tan² θ = 1

Hence we can write this as :

( sec θ + tan θ )( sec θ - tan θ ) = 1

= > l ( sec θ - tan θ ) = 1

= > sec θ - tan θ = 1 / l ...............( 2 )

Adding ( 1 ) and ( 2 ) we get :

2 sec θ = l + 1 / l

= > 2 sec θ = ( l² + 1 ) / l

= > sec θ = ( l² + 1 ) / 2 l

Hence proved .

Answer 2

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