Question

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Secondary SchoolMath 5 points


If Raj is 40% more efficient than Pooja,then Pooja is deficient than Raj by ( approximately) .answer this question?

Answer 1

Answer:

• If Raj is 40% more efficient than Pooja, then Pooja is deficient than Raj by 29%.

Step-by-step explanation:

• It is given that Raj is 40% more efficient than Pooja.

Assumption:

• Let raj's efficiency be x.
• Let Pooja's efficiency be y

Here, To solve this Question, We have a Formula;

• Formula(Y)= [(x/(100 + x)×100]%

Substitute given value in Formula:

• Y = [ 40/(100 + 40) × 100]%
• Y = [ 40/140×100]%
• Y = 20/70×100
• Y = 2/7 × 100
• Y = 200/7 %
• Y = 28.57 0r 29%

Therefore, If Raj is 40% more efficient than Pooja, then Pooja is deficient than Raj by 29%.

Answer 2

Answer:

If Raj is 40% more efficient than Pooja, Pooja is deficient than Raj by approximately 29%.

Step-by-step explanation:

Given,

Raj is 40% more efficient than Pooja.

Let us assume that Raj's efficiency be x.

Let us assume that Pooja's efficiency be y.

By using this formula, we can solve this question.

y = [{x / (100 + x)} × 100]%

Now, putting the given values.

=> y = [{x / (100 + x)} × 100]%

=> y = [{40 / (100 + 40)} × 100]%

=> y = [(40 / 140) × 100]%

=> y = [(4 / 14) × 100]%

=> y = [(2 / 7) × 100]%

=> y = [(200 / 7)]%

=> y = 200/7%

=> y = 28.57%

=> y = 28.57% ≈ 29%

.°. y = 28.57% ≈ 29%

Therefore, If Raj is 40% more efficient than Pooja, Pooja is deficient than Raj by approximately 29%.