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3x+5y = 11 ; xy = 2
3x+5y = 11
» squaring on both sides,
(3x+5y)² = 11²
(3x)² + (5y)² + 2(3x)(5y) = 121
9x² + 25y² + 30xy = 121
9x² + 25y² + 30(2) = 121
9x²+25y² = 121 - 60
9x²+25y² = 61
Therefore,9x²+25y² = 61
3x+5y = 11
» squaring on both sides,
(3x+5y)² = 11²
(3x)² + (5y)² + 2(3x)(5y) = 121
9x² + 25y² + 30xy = 121
9x² + 25y² + 30(2) = 121
9x²+25y² = 121 - 60
9x²+25y² = 61
Therefore,9x²+25y² = 61
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