Math, asked by MrPlatinum, 14 days ago

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$ \Large \mathtt \red{Question :}$
Write the principle value of $ \sf{cos^{-1}\{cos(680)°\} }$.
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Answers

Answered by varshinigowda8
5

Answer:

¿?●HEY FREIND●¿?

Step-by-step explanation:

cos−1[cos(680o)]

=cos−1[cos(2×360−40)]

=cos−1[cos40o]

=40o

Answered by IIGeniusAfrinII
8

  \huge \bold \pink{answer}

  • Principal value of cos-1(cos680∘) will lie between 0 and 180∘. So, principal value of given expression is 40∘.

genius Áfríñ ✔️

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