Math, asked by Anonymous, 1 month ago

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If one root of the equation 
 {x}^{2}  + px + 12 = 0
is 4 , while the equation
 {x}^{2}  + px + q = 0
has equal roots then the value of q is ​

Answers

Answered by scp096
1

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Answered by llAngelsnowflakesll
28

One root of the equation x² + px + 12 = 0

is 4

+16 + 4p + 12 = 0

..p= -7

as x² + px +q=has equal roots.

b2 = 4ac p= 4q

49 =4

Hence proved

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