Brainly Users please help@I beg you
The top of a ladder 17 m long when placed against a wall reaches the height of 15m. How far is the foot of the ladder away from the wall.
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HEY MATE !
WE CAN FIND THE ANSWER THROUGH PYTHAGORAS THEOREM
height of ladder = 15m
length of hypotenuse = 17m
Therefore base = distance of ladder from wall (Which we have to find)
So....
base ^2 = hypotenuse^2 - height^2
base ^2 = 17 ^2 - 15^2
base ^2 = 289 - 225
base ^2 = 64
therefore base = square root of 64 = 8
there fore distance of ladder from wall is 8m
HOPE IT HELPS MATE!
WE CAN FIND THE ANSWER THROUGH PYTHAGORAS THEOREM
height of ladder = 15m
length of hypotenuse = 17m
Therefore base = distance of ladder from wall (Which we have to find)
So....
base ^2 = hypotenuse^2 - height^2
base ^2 = 17 ^2 - 15^2
base ^2 = 289 - 225
base ^2 = 64
therefore base = square root of 64 = 8
there fore distance of ladder from wall is 8m
HOPE IT HELPS MATE!
rehannadeem2007:
Um there's a little mistake
the square root of 64 is not 4
it's 8
oh yeah !..ummm...sorry I was In a hurry...and thanks for reminding
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