Question

brainly users plz helps me and others plz dont delete this quest. i will mark as brainliest and give 5 thanks to his / her answers .
plz dont post irrelevant answers otherwise i will report it.....​

Answer 1

Answer:

Mole of aluminium oxide (Al2O3) = 2 x 27 + 3 x 16

= 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / 102 x 0.051 molecules

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.

Step-by-step explanation:

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Answer 2

Answer:

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