brainly users, plz solve this
class 10 cbse
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Answered by
1
Answer:
ax+by=a-b
ax=a-b-by
x=a-b-by/a←
bx-ay=a+b
substituting
b(a-b-by/a)-ay=a+b
ab-b²-b²y/a-ay=a+b
ab-b²-b²y-a²y/a=a+b
ab-b²-(b²+a²)y=a²+ab
-(b²+a²)y=a²+ab-ab+b²
(b²+a²)y=-(a²+b²)
y=-(a²+b²)/a²+b²
y=-1←
substituting value of y
x=a-b-b(-1)/a
x=a-b+b/a
x=a/a
x=
mohithaarv:
May I know how u got the answer
Answered by
0
Answer:
Step-by-step explanation:
ax + by = a - b ........ (1)
bx - ay = a + b....... (2)
(1) x a & (2) x b
a^2 x + aby = a^2 - ab......... (3)
b^2 x - aby = ab + b^2........ (4)
(3) + (4) gives
x (a^2 + b^2) = a^2+b^2
x = 1
Substitute x = 1 in equation (1) we get,
a + by = a - b
by = - b
y = - 1
The solution is x = 1 and y = -1.
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