Question

Pls do this with steps...then I will mark your answer as brainlist

Answer 1

$\textbf{\huge{ANSWER:}}$

Given:

Angle A = 125°

To find:

Angle D

Solution:

In a ||gm, opposite sides are parallel to each other.

Thus,
AB || CD

Now, AB || CD and AD is a traversal intersecting both of them

Angle A + Angle D = 180° ( co-interior angles )

=》 125° + Angle D = 180°

=》 Angle D = 180° - 125°

=》 $\textbf{Angle D = 55°}$

Hope it Helps!! :)

Answer 2

Answer:

∠D = 55°

Step-by-step explanation:

Given that ABCD is a parallelogram in which ∠A = 125°.

∴ Sum of any two adjacent angles of a parallelogram is 180°.

⇒ ∠A + ∠B = 180°

⇒ 125° + ∠B = 180°

⇒ ∠B = 180° - 125°

⇒ ∠B = 55°

(i)

Also, ∠B + ∠C = 180° {Since, ∠B and ∠C are adjacent angles}

⇒ 55° + ∠C = 180°

⇒ ∠C = 180° - 55°

⇒ ∠C = 125°.

(ii)

Further, ∠C + ∠D = 180°{Since, ∠C and ∠D are adjacent angles}

⇒ 125° + ∠D = 180°

⇒ ∠D = 180° - 125°

⇒ ∠D =  55°

Therefore, ∠D = 55°.

Hope it helps!