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11.
To find the answer we need to calculate the LCM of 5 and 2.
The cube with each sides measuring equal to the LCM will give the dimensions of required cube.
LCM of 5 and 2 = 10
Volume of cuboid = 5 x 5 x 2 cubic cms
Volume of bigger cube=103=1000 cubic cms
Number of cuboids required to make the bigger cube = volume of bigger cube/ volume of cuboid
= 1000/50
=20
12)
Total soaps = 216 cube root of 216= 6
Thus length of each side of the bigger cube is 6 units thus first row has 6*6 = 36 soaps.
There are total 6 such rows comprising of 216 soaps.
To find the answer we need to calculate the LCM of 5 and 2.
The cube with each sides measuring equal to the LCM will give the dimensions of required cube.
LCM of 5 and 2 = 10
Volume of cuboid = 5 x 5 x 2 cubic cms
Volume of bigger cube=103=1000 cubic cms
Number of cuboids required to make the bigger cube = volume of bigger cube/ volume of cuboid
= 1000/50
=20
12)
Total soaps = 216 cube root of 216= 6
Thus length of each side of the bigger cube is 6 units thus first row has 6*6 = 36 soaps.
There are total 6 such rows comprising of 216 soaps.
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12) ∛216=6
Ans. = 6
11) Length of each edge of cube = L.C.M. of 2 cm. ,
5 cm . and 5 cm.. i,e 10 cm.
Numbers of cuboids =(Volume of cube )/(Volume of cuboid).
=(10 cm ×10 cm ×10 cm)/(2 cm ×5 cm ×5 cm).
=5 ×2 ×2
=20 cuboids
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