Question

Brakes applied to a car produce a uniform acceleration of 90. If the car was travelling with a velocity of 27 then what distance will it cover before coming to rest

Answer 1

Your are not given the unit so I gave S.I( standard international) units of this quantity

acceleration = a = -90m/s²

intial velocity = u = 27m/s

final velocity = v = 0 m/s

distance = s = ?
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v²-u² = 2as

(0)²-(27)² = 2(-90)(s)

0 - 729 = -180s

-729 = -180s

-729/-180 = s

4.05 m = s
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so car travel 4.05 distance when it apply the brake before going to rest

Answer 2

using the law of motion .

S=v2-u2/2a

S = 0×0-27×27/2×-90=4.05

hence we get that the car travels 4.05 meter/s befor it came to rest