Question

brakes applied to a car produce an acceleration of 6m/s in opposide direction to motion if the car takes 2s to stop after application of brakes then calculate the distance it travels during this time

Answer 1

v=0
a=-6 m/s^2
t=2s
s=?
v=u+at
u=12 m/s
s=ut+1/2 at^2
s=12m.

Answer 2

${\tt{\red{\underline{\underline{\huge{Answer:}}}}}}$

Step-by-step explanation:

Given,

Acceleration, a = -6 m/s²

Time taken,  t = 2 s

Final velocity, v = 0 m/s (As it stops.)

To Find,

Distance travelled, s = ?

Formula to be used,

1st equation of motion, v = u + at

2nd equation of motion, s = ut + 1/2 at²

Solution,

Putting all the values, we get

v = u + at

⇒ 0 = u + (- 6) × 2

⇒ u = 12 m/s

Here, the initial velocity is 12 m/s.

Now, the distance travelled,

s = ut + 1/2 at²

⇒ s = 12 × 2 + 1/2 × (- 6) × 2²

⇒ s = 24 - 12

⇒ s = 12 m

Hence,the distance travelled is 12 m.