brakes applied to a car produces a uniform retardation of 0.9 m/s .If the car was moving with avelocity of 27 m/s.What distance will it cover before coming to rest...
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Answer:
1312.2 m
Explanation:
a= -0.9m/s
u=27m/s
v=0m/s
By using
2as=v^2-u^2
2×(-0.9)×s=0-(27)^2
-1.8s= - 729
s= -729/-1.8
s=1312.2 m
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