Question

Brass wire has to carry load of 5 Kg. If Y for brass is 1.2 x 10 5 N/mm2

find diameter of wire; if

elastic limit for brass is not to be exceeded. Elastic limit for brass is 120 N/mm2
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Answer 1

Given: Brass wire has to carry load of 5 kg. Elastic limit for brass is 120 N/mm^2. Elastic limit for brass is not to be exceeded.

To find: Diameter of wire

Explanation: Let the mass be m, weight be w, radius be r and diameter be d.

m= 5 kg

w = m× g

= 5 × 10

= 50 N

Therefore, a force of 50 N stretches the brass wire.

$area = \pi {r}^{2}$

$area = \frac{\pi {d}^{2} }{4}$

$area = 0.785 {d}^{2}$

(since π = 3.14)

Elastic limit is the maximum stretch a solid can handle without getting deformed completely.

Elastic limit is given by the formula:

Elastic limit= Force/ Area

$= > 120 = \frac{50}{0.785 {d}^{2} }$

$= > 0.785 {d}^{2} = \frac{50}{120}$

$= > {d}^{2} = \frac{50}{120 \times 0.785}$

$= > {d}^{2} = 0.5307$

=> d = 0.7285 mm

Therefore, the diameter of the wire is 0.7285 mm.