Physics, asked by Afreen198, 1 year ago

Breaks are applied on a train moving with speed of 90km/h it stopped in 1 minute finds its retardation

Answers

Answered by arvindhan14
0

Answer:

5/12 m/s²

Explanation:

Initial Velocity, u = 90 km/h = 90*5/18 = 25 m/s.

Final Velocity, v = 0 m/s. [Since the train is stopped]

Time = 1 min = 60 secs

Acceleration = (v - u)/t = (0 - 25)/60 = -25/60

= -5/12 m/s²

Retardation = Negative acceleration = 5/12 m/s²

Hope this helps.

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