Breaks are applied on a train moving with speed of 90km/h it stopped in 1 minute finds its retardation
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Answer:
5/12 m/s²
Explanation:
Initial Velocity, u = 90 km/h = 90*5/18 = 25 m/s.
Final Velocity, v = 0 m/s. [Since the train is stopped]
Time = 1 min = 60 secs
Acceleration = (v - u)/t = (0 - 25)/60 = -25/60
= -5/12 m/s²
Retardation = Negative acceleration = 5/12 m/s²
Hope this helps.
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