Math, asked by Briannapcharles, 8 months ago

Brian just finished three paintings. He makes his own frames for each painting. The first painting is 42cm by 42 cm;the second is 60cm by 36cm and third is 84cm by 24cm. How many cm of wood does Brian need to frame all three paintings? PLEASE ANSWER STEP BY STEP

Answers

Answered by sona972
0

Step-by-step explanation:

perimeter of first painting =2(42+42)=2*84=168 cm

perimeter of second painting =2(60+36)=2*96=192 cm

perimeter of third painting =2(84+24)=2*108=216 cm

total wood required =168+192+216

=576cm

hope this helps you

Answered by Sauron
3

Answer:

Total 576 cm wood required to frame all paintings

Step-by-step explanation:

1). First painting =

42cm by 42 cm

2). Second painting =

60cm by 36cm

3). Third painting =

84cm by 24cm

First find the perimeter

As we know,

Formula of perimeter = 2 ( length + width)

So,

1). 2 ( 42 + 42)

➨ 2 × 84

168

2). 2 (60 + 36)

➨ 2 × 96

192

3). 2 (84 + 24)

➨ 2 × 108

216

According to question:

➨ 168 cm + 192 cm + 216 cm

576 cm

Therefore,

Total 576 cm wood required to frame all paintings

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