Briefly analyse the position of the President in Indian parliamentary democracy
Answers
Explanation:
Given -
BE and CF are 2 equal altitudes.
To find -
That ∆ABC is an isosceles triangle.
Solution -
In ∆BCF and ∆CBE
→ \angle∠ BFC = \angle∠ CBE (Both 90°)
→ BC = BC (common)
→ FC = CB (Given)
\therefore∴ ∆BCF ≈ ∆CBE (RHS rule)
So,
\angle∠ FCB = \angle∠ ECB (CPCT)
Similarly -
AB = AC (Side opposite to the equal angles of a triangle are also equal)
\therefore∴ ∆ABC is an isosceles triangle.
Hence, proved!
Some more rules of a Triangle -
ASA rule
When 2 angles and one side of a Triangle are equal to the 2 angles and one side of another Triangle. Then Triangles are congurent.
SAS rule
When 2 sides and one angle of a triangle are equal to the 2 sides and one angle of another Triangle. Then Triangles are congurent.
SSS rule
If 3 sides of a Triangle are equal to the 3 sides of another Triangle. Then Triangles are congurent.
RHS rule
If in 2 right triangles the hypotenuse and one side of one Triangle are equal to the hypotenuse and one angle of another Triangle. Then Triangles are congurent.
AAS rule
When 2 angles and one sides are equal to 2 angles and one side of a Triangle. Then Triangles are congurent.
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