Briefly summarise the poem An Old Women
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Method 1:
Area of ABCD is 1.
Area of PQRS = (1/2)*(diagonal1)*(diagonal2)
Both diagonals of PQRS are 1 each since they are the same lengths as sides of ABCD
Area of PQRS = (1/2)*1*1 = 1/2
Area of leftover region = 1 - 1/2 = 1/2
The leftover region after you cut out PQRS is split into 8 equal areas and the red region is one of those 8.
Hence area of red region is (1/8)*(1/2) = 1/16
Method 2:
The perimeter of ABCD is 4 so each side is 1. So each half side is 1/2.
In triangle APQ, AP and AQ are 1/2 each so PQ=1/2√PQ=1/2 (using Pythegorean theorem)
So half of PQ is 1/22√1/22
Area of red triangle = (1/2)∗(1/22√)∗(1/22√)=1/16
Area of ABCD is 1.
Area of PQRS = (1/2)*(diagonal1)*(diagonal2)
Both diagonals of PQRS are 1 each since they are the same lengths as sides of ABCD
Area of PQRS = (1/2)*1*1 = 1/2
Area of leftover region = 1 - 1/2 = 1/2
The leftover region after you cut out PQRS is split into 8 equal areas and the red region is one of those 8.
Hence area of red region is (1/8)*(1/2) = 1/16
Method 2:
The perimeter of ABCD is 4 so each side is 1. So each half side is 1/2.
In triangle APQ, AP and AQ are 1/2 each so PQ=1/2√PQ=1/2 (using Pythegorean theorem)
So half of PQ is 1/22√1/22
Area of red triangle = (1/2)∗(1/22√)∗(1/22√)=1/16
arnavagrawal22:
sorroy written by mistake
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