Question

Bro plzz give me the answer

Answer 1

the difference of consecutive terms of an AP are equal.
therefore;
( 2k^2+3k+6)-(k^2+4k+8)=
(3k^2+4k+4)-(2k^2+3k+6)
2k^2+3k+6-k^2-4k+8 = 3k^2+4k+4-2k^2-3k-6
k^2-k+14 = k^2+k-2
2k=6
k=8