Brown eyes in humans are dominant to blue eyes. A brown-eyed man, whose mother was
blue-eyed, marries a brown-eyed woman whose father had blue eyes. What is the probability that this couple will have a blue-eyed child?
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Your parents are both heterozygous for the pigment-producing gene that makes the iris brown. Each had a parent devoid of the pigment gene, so neither could have inherited a pigment gene from both parents. Name the dominant pigment allele A and the inactive allele a.The man and woman are both Aa-one of each allele. It only takes one Aallele to give brown eyes. Each parent gives a child one allele.
There is therefore one chance in four for each of these possibilities: one allele from each parent, in order:
AA (brown eyes)
Aa (brown eyes)
aA (brown eyes)
aa (blue eyes)
Therefore there is a 1:4 chance of having a blue-eyed child.
There is therefore one chance in four for each of these possibilities: one allele from each parent, in order:
AA (brown eyes)
Aa (brown eyes)
aA (brown eyes)
aa (blue eyes)
Therefore there is a 1:4 chance of having a blue-eyed child.
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