Question

Brut
2. Find the value of root 12 following up to 3 decimal places if root 3 is 1.732

Answer 1

$\sqrt{12 } = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2 \times \sqrt{3} \\ \sqrt{12} = 2 \times 1.732 \\ \sqrt{12} = 3.464$

Answer 2

Answer:

Required value of √12 is 3.464.

Step-by-step explanation:

Here we want to find value of

$\sqrt{12}$

Given value of

$\sqrt{3} = 1.732$

Now,

$\sqrt{12} \\ = \sqrt{2 \times 2 \times 3 } \\ = 2 \sqrt{3} \\ = 2 \times 1.732 \\ = 3.464$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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