Question

Hlo guys...yrr ye solve krdoo..the sumbif three consecutive multiples of 8 is 888.Find the multiples.​

Answer 1

Answer:

LET THE MULTIPLES BE 8X,8(X+1),8(X+2)

ACCORDING TO THE QUESTION

8X+8(X+1)+8(X+2) = 888

8X+ 8X+ 8+8X+16= 888

24X+24=888

24X= 888-24

24X=864

X=864/24=36

MULTIPLES = 8X = 8*36=288

8(X+1)= 8(36+1)= 8*37= 296

8(X+2)=8(36+2)= 8*38= 304

Answer 2

Explanation:

Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 888

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

Take 24 on the RHS

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304

If we sum up these three multiples i.e (288 + 296 + 304) we get 888.

thanks

Mark as brainliest if this helps u