Question

bta do koi please class8 ch factorisation​

Answer 1

Step-by-step explanation:

answer of first is -2⁷ for a^x × a^y = a^x+y

and for second do reciprocal for first number it will become 9²/5² and for the last one is 0 because a⁰ = 1

so we get

9²/5² × 3^-3/5^-3

do reciprocal for second one

9²/5² × 3³/5³

since 3²=9 we can write 9²=3³

= 3³/5² × 3³/5³

for a^x × a^y = a^x+y

3³+³/5²+5³ = 3⁶/5⁵

ANSWERS - (1ST) -2⁷ AND FOR SECOND 3⁶/5⁵