Question

btained by heatin
5.6 g of calcium oxide is obtainer
nitrate according to the equation :
2Ca(NO3)2 → 2CaO + 4NO, +
Calculate :
(a) volume of NO2 evolved at STP and
(b) the mass of calcium nitrate heated.
​

Answer 1

Answer:

) - given the stoichiometric coefficients, we know that 2 moles of Ca(NO3)2 will produce 4 moles of NO2, hence, 1 mole will produce 2 moles of NO2

2) - 328 g produces 22.4 L, since One mole of any gas at S.T.P. occupies the same volume which is 22.4 L.

Hence, 65.6 g produces (65.6*22.4)/328 = 4.48 L

3) - 328 g produces 112 g CaO. Therefore, 65.6 g produces = (65.6*112)/328 = 22.4 g CaO. 

4) - Given the stoichiometric coefficients, we know 5 moles of gaseous products are already being produces ( 4+1) by 2 moles of reactant.

5) - 44.8 L at STP = 2 moles of NO2, since One mole of any gas at S.T.P. occupies the same volume which is 22.4 L.

Hence, to produce 2 moles of NO2, we need 1 mole of reactant = 164 g

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Answer 2

Calcium nitrate decomposed on heating according to the equation: 2 Ca(NO3)2 - 2CaO + 4NO2 + O2 The molecular mass of calcium nitrate is 164 u. ... the volume of nitrogen dioxide (NO2) obtained at S.T.P. a the weight of calcium oxide obtained when 16.4 g of calcium nitrate is heated to constant weight.