Question

BTS ARMY DON'T SPAM
irreverent answers would be reported! Answer the questions step by step!
.
Q1. sin50°/cos40°+cosec40°/ sec50°-4cos50°cosec40°
.
best answer would be marked as brainliest!!!​

Answer 1

Hey Pretty Stranger!

★ sin 50°/cos40° + cosec40°/sec 50 - 4cos50° × cosec40°

→ sin 50/ cos 40 + cos 50/ sin 40  - 4 cos 50 /sin 40

  ∵ cosec A= 1/sin A and sec A= 1/cos A

→ cos(90-50)/cos 40+ sin(90-50)/sin 40 - 4 sin(90-50)/sin 40

∵ cos A= sin (90-A) and sin A= cos (90-A)

→ cos 40/cos 40 + sin 40/sin 40 - 4 sin 40/sin 40

→ 1 + 1 - 4 × 1

→ 1 + 1 - 4

→ 2 - 4

→ - 2

$\therefore$ sin 50°/cos40° + cosec40°/sec 50 - 4cos50° × cosec40° = -2

Answer 2

Answer:

hey ARMY thanks for following me

I purple you