Budhan covers a distance of 19 km in 2 hours by cycling one fourth of the time and walking the rest.The next day he cycles(at the same speed a before) for half the time and walks the rest(at the same speed as before) and covers 26 km in 2 hours. The speed in which budan walks is
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The speed in which budan walks is 6 km/hr
Explanation :
Let the speed of cycling = x km/hr
speed of walking = y km/hr
case-I
time of cycling = 2/4 = 0.5 hr
=> distance covered by cycling = 0.5x
time of walking = 2 - 0.5 = 1.5 hr
=> distance covered by walking = 1.5y
hence
0.5x + 1.5y = 19............eq1
case-II
time of cycling = 2/2 = 1 hr
=> distance covered by cycling = 1 *x = x
time of walking = 2 - 1 = 1 hr
=> distance covered by walking = 1*y = y
hence
x + y = 26............eq2
solving both eq1 and eq2 we get
x = 20 km/hr
y = 6 km/hr
Hence the speed in which budan walks is 6 km/hr
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