Bulb 220v and 10 w how many such bulbs in 220v 5a in parallel
Answers
Answered by
0
maximum resistance=220/5=44ohm
now use
n*p=v*v/r
where r is resistance,v is potential, pis power(10)
now use
n*p=v*v/r
where r is resistance,v is potential, pis power(10)
Answered by
0
110( I guess)220×220÷R=10 Which gives value of resistance as 4840 ohm..Then 220÷5 =44 then dividing 4840 by 44 gives 110..
Similar questions