Question

bullet of mass 0.04 kg moving with a speed of 10 metre per second ends the average wood block and its stopping after the distance of 60 cm what is the average responded for the external by the block on the bullet​

Answer 1

Answer:

Given,

m=0.04kg

u=90m/s

v=0m/s

S=60cm

From 3rd equation of motion,

2aS=v^2 − u^2

a = − u^2

2S

a = − 90×90 =−6750m/s^2

2×60×10^−2

The resistive force, f=ma

f=−0.04×67.5

f=−270N

Explanation:

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