Question

bullet of mass 10g is fired horizontally with a velocity of 240m/s from a pistol of mass 1.2kg.What is the recoil velocity of the pistol​

Answer 1

$\small\bold{\underline{\sf{\purple{Given:-}}}}$

• Mass of bullet = 10g = 0.01kg
• Mass of pistol = 1.2kg
• Velocity of bullet = 240m/s

$\small\bold{\underline{\sf{\pink{To\:Find:-}}}}$

• recoil velocity of gun.

$\small\bold{\underline{\sf{\orange{Explanation:-}}}}$

Here, No net force acts on the whole system so we can apply concept of momentum conservation.

Initial momentum of whole system will be zero (i.e., at rest)

As per law of momentum conservation, initial momentum of system will be equal to the final momentum of system.

➝ P_initial = P_final

➝ 0 = MV + mv

➝ V = -mv/M

➝ V = -(0.01×240)/1.2

➝ V = -2m/s

[፨ Negative sign shows opposite direction.]

Answer 2

Answer:

- 2 m/s is the recoil velocity of the gun in which the negative sign implies that the gun moves in the direction opposite to that of the bullet.

Explanation:

Refer the attachment.