Question

Bullet of mass 20g moving with a speed of 500 m/s-1 strikes a wooden block of mass 1kg and gets ambedded in it. Find the speed with which block moves along with the bullet.

Answer 1

Apply the principle of conservation of momentum here .

Mass of bullet = m = 20g or 20×10-³ Kg

Mass of block = M = 1 kg

Initial speed of bullet (v1) = 500m/s

final speed of bullet(v2) = 0

Initial speed of block (V1) = 0

Final speed of block (V2) = ❔

we know according to principal of conservation of linear momentum :- Initial momentum of the system = final momentum of the system .

so

M1V1 + m1v1 = M2V2 + m2v2

Now plug in the values , we get

1×0 + 20×10-³×500 = 1×V2 + 20×10^-³ ×0

=> V2 = 10000 ×10-³

=> V2 = 10m/s.

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