Question

Bullet weighing 200 g is fired horizontally with a velocity of 25 m/sec from a gun carried on a carriage which together with the gun weighs 100 kg. The velocity of recoil of the gun, will be

Answer 1

Explanation:

as per conservation of momentum principle

0.2*25 = 100*v

v = 5/100 = 0.05 m/s

so recoil velocity of gun is 0.05 m/s