Question

bulleted of 5 kg is fired with the mass of 2kg if after firing the bullet goes at the speed of 5m/s .find recoiling velocity of a gun​

Answer 1

Momentum before firing = Momentum after firing [ Due to Conservation of Momentum ]

m1u1(Gun) + m1u2(Bullet) = m2v1(Gun) + m2v2(Bullet)

2×0 + 5×0 = 2×v + 5×5

0 = 2v + 25

2v = -25

v = -25/2

Recoil Velocity = -12.5 m/s