Question

Bus accelerates uniformly from 54 km/h to 72 km/h in 10 seconds. calculate its acceleration.

Answer 1

Answer:

Initial velocity =54km/hr

Final velocity =72km/hr

Change in velocity =Vf-Vi

=18km/hr

Acceleration

= change in velocity / time

=18/10=1.8m/s^2

Answer 2

Explanation:

$u = 54km {hr}^{ - 1} = (54 \times \frac{5}{18 })m {sec}^{ - 1} = 15m {sec}^{ - 1} \\ \\ v = 72km {hr}^{ - 1} = (72 \times \frac{5}{18} )m {sec}^{ - 1} = 20m {sec}^{ - 1} \\ \\ t = 10sec \\ \\ v = u + at \\ \\ 20 = 15 + a(10) \\ \\ 5 = 10a \\ \\ a = 0.5 \: m {sec}^{ - 2}$

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