bus accelerates uniformly from 54km/h to 72 km/h in s calculate acceleration in m/s^2
Anonymous:
mention time man
Answers
Answered by
4
hey dude
here is your answer
=============
u=54km/hr
54*5/18=15m/s
v=72km/hr
72*5/18=20m/s
a=(v-u)/t
(20-15)/10
5/10=0.5
=============
hope it will help you.
here is your answer
=============
u=54km/hr
54*5/18=15m/s
v=72km/hr
72*5/18=20m/s
a=(v-u)/t
(20-15)/10
5/10=0.5
=============
hope it will help you.
Answered by
3
I am taking the time to be t as it is not mentioned
so, initial velocity = 54 km/ hr =15m/s
final velocity= 72 km/hr = 20m/s
acceleration = (v-u)/t = 5 / t m/s^2
if t= 10 sec, a = 0.5 m/s^2
so, initial velocity = 54 km/ hr =15m/s
final velocity= 72 km/hr = 20m/s
acceleration = (v-u)/t = 5 / t m/s^2
if t= 10 sec, a = 0.5 m/s^2
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