Question

bus is travelling in a constant speed of 28 metre per second .a car is 200 metres behind the bus and begins to accelerate East at 4 metre per second square starting from an initial speed of 30 metre per second how long will it take the car to catch up to the bus

the best answer will be marked as brainlist . please answer it fast ​

Answer 1

Explanation:

Speed of bus, b = 28 m/s

initial speed of car, c = 30m/s

acceleration, a = 4m/s^2

initial distance between them = 200m

Let's say he car catches up to the bus in t seconds

then distance travelled by car in t seconds = 200 + distance travelled by bus in t seconds

=> ct + 1/2 at^2 = 200 + bt

=> 30t + 1/2 × 4 × t^2 = 200 + 28t

=> 30t + 2t^2 - 200 -28t = 0

=> 2t^2 + 2t -200 = 0

=> t^2 + t - 100 = 0

Solve the equation for t.

t = [-1 + √401 ]/2 ~ 9.5seconds.

it will take approximately 9.5 seconds.

to get exact answer, calculate t exactly.