Question

bus starts from rest and moves with uniform acceleration of 1 m/s² for 5 minutes. Calculate the distance travelled by the bus

Answer 1

GiveN :

• Initial velocity (u) = 0 m/s
• Acceleration (a) = 1 m/s²
• Time interval (t) = 5 minutes

To FinD :

• Distance travelled by the bus.

SolutioN :

The bus starts from rest, it means it was initially at rest. So, we'll take initial velocity as 0 m/s².

Convert time into seconds from minutes

⇒Time = 5 minutes

⇒Time = 5 * 60

⇒Time = 300 seconds

_______________________

Now, use 2nd equation of Kinematics

⇒s = ut + ½at²

⇒s = 0 * 300 + ½ * 1 * (300)²

⇒s = 0 + ½ * 1 * 90000

⇒s = 90000/2

⇒s = 45000 m

⇒s = 45 km

∴ Distance travelled by bus is 45000 m or 45 km.

Answer 2

Answer:

45 km

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Acceleration of the bus = a = 1 m/s²

• Time taken = t = 5 minutes = 300 seconds

To find :

• Distance travelled by the bus

Using the second equation of motion :

S=ut+½×at²

S=0×300+½×1×300²

S=0+0.5×90000

S=0+45,000

S=45,000 metres

1000 metres = 1 km

45,000 m = 45 km

The distance travelled by the bus in this time period is equal to 45 km

Extra :

• First equation of motion = V=u+at

• Third equation of motion = v²-u²=2as