Math, asked by gargakshay0007, 2 months ago

bus travelling at an average speed of 50 km per hour have made the trip to turn in 6 hours if it had travelled at 45 kilometre per hour how many minutes will it have taken to make the trip​

Answers

Answered by TheBrainliestUser
59

Given that:

  • Bus travelling at an average speed of 50 km per hour have made the trip to turn in 6 hours.

To Find:

  • If it had travelled at 45 kilometre per hour how many minutes will it have taken to make the trip.

We know that:

  • Distance = Speed × Time

We have:

  • Speed = 50 km/hr
  • Time = 6 hrs

Finding the total distance:

↣ Distance = 50 × 6

↣ Distance = 300 km

Now we have:

  • Distance = 300 km
  • Speed = 45 km/hr

Finding the time:

↣ 300 = 45 × Time

↣ Time = 300/45

↣ Time = 6 2⁄3 hrs

Finding the difference between both time:

↣ Difference = (6 2⁄3 - 6) hrs

↣ Difference = 2⁄3 hrs

Converting into minutes:

  • 1 hr = 60 minutes
  • 2⁄3 hrs = 2⁄3 × 60 = 40 minutes

Hence,

  • It will take 40 minutes more to make the trip.
Answered by Anonymous
113

Answer:

Given :-

  • A bus travelling at an average speed of 50 km/hr have made the trip to turn in 6 hours if it had travelled at 45 km/hr.

To Find :-

  • How many minutes will it have taken to make the trip.

\clubsuit Distance Formula :

\mapsto \sf\boxed{\bold{\pink{Distance =\: Speed \times Time}}}

Solution :-

Given :

  • Speed = 50 km/hr
  • Time = 6 hours

According to the question by using the formula we get,

\implies \sf Distance =\: 50 \times 6

\implies \sf\bold{\purple{Distance =\: 300\: km}}

Again,

Given :

  • Distance = 300 km
  • Speed = 45 km/hr

According to the question by using the formula we get,

\implies \sf 300 =\: 45 \times Time

\implies \sf \dfrac{300}{45} =\: Time

\implies \sf 6\dfrac{2}{3} =\: Time

\implies \sf\bold{\purple{Time =\: 6\dfrac{2}{3}}}

Now, we have to find the difference between the both time given :

Given :

  • Time = 6 hours
  • Time = 6⅔ hours

Hence,

\implies \sf Difference\: between\: both\: time =\: \bigg(6\dfrac{2}{3} - 6\bigg)\: hours

\implies \sf \bold{\purple{Difference\: between\: both\: time =\: \dfrac{2}{3}\: hours}}

Now, we have to convert the time into minutes :

\longrightarrow \sf Time =\: \dfrac{2}{3}\: hours

\longrightarrow \sf Time =\: \dfrac{2}{3} \times 60\: minutes\: \: \bigg\lgroup \sf\bold{\pink{1\: hours =\: 60\: minutes}}\bigg\rgroup

\longrightarrow \sf Time =\: \dfrac{\cancel{120}}{\cancel{3}}\: minutes

\longrightarrow \sf Time =\: \dfrac{40}{1}\: minutes

\longrightarrow \sf\bold{\red{ Time =\: 40\: minutes}}

{\small{\bold{\underline{\therefore\: In\: 40\: minutes\: will\: it\: have\: taken\: to\: make\: the\: trip\: .}}}}\\

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