Question

bx/a+ay/b=a^2+b^2; x+y=2ab

Answer 1

Answer:

The solution of system of equation x=ab and y=ab

Step-by-step explanation:

Given: System of equation

$\frac{b}{a}x+\frac{a}{b}y=a^2+b^2$---------(1)

$x+y=2ab$-----------(2)

Using elimination method to solve for x and y

Multiply second equation by -b/a to eliminate x

$-\frac{b}{a}x-\frac{b}{a}y=-\frac{b}{a}\cdot 2ab$

$\frac{b}{a}x+\frac{a}{b}y=a^2+b^2$

Add both equation to eliminate x

$\frac{a}{b}y-\frac{b}{a}y=a^2+b^2-\frac{b}{a}\cdot 2ab$

$y(\dfrac{a^2-b^2}{ab})=a^2-b^2$

$y=ab$

Substitute y=ab into equation (2)

$x+ab=2ab$

$x=ab$

Hence, The solution of system of equation x=ab and y=ab

Answer 2

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