Question

bx/a-ay/b+a+b=0
bx-ay+2ab=0

solve this linear equation in 2 variables by Elimination Method

Answer 1

Elimination method.

⇒ (b2x - a2y  + a2b +ab 2) / ab = 0 and (bx) - (ay) + 2ab = 0
⇒ (b2x - a2y  + a2b +ab 2) = 0 ---------→(1)
⇒ (bx) - (ay) + 2ab = 0    ---------→(2)
Multiply equation (2) by b
(b2x) - (aby) + 2ab2 = 0            ---------→(3)
Substract (3) from (1)
⇒ - a2y + aby + a2b +ab 2 -2ab2  = 0
⇒ y(ab – a2) = ab2-a2b
⇒ ya(b – a) = ab(b-a)
⇒ y = b
sub y =b in equ (2)
we get (bx) - (ab) + 2ab = 0
⇒ b(x + a) =0
⇒ x+a = 0
⇒ x = -a. and y =b.

hope it helps!!!

Answer 2

Answer:

Step-by-step explanation:Elimination method.

⇒ (b2x - a2y  + a2b +ab 2) / ab = 0 and (bx) - (ay) + 2ab = 0

⇒ (b2x - a2y  + a2b +ab 2) = 0 ---------→(1)

⇒ (bx) - (ay) + 2ab = 0    ---------→(2)

Multiply equation (2) by b

(b2x) - (aby) + 2ab2 = 0            ---------→(3)

Substract (3) from (1)

⇒ - a2y + aby + a2b +ab 2 -2ab2  = 0

⇒ y(ab – a2) = ab2-a2b

⇒ ya(b – a) = ab(b-a)

⇒ y = b

sub y =b in equ (2)

we get (bx) - (ab) + 2ab = 0

⇒ b(x + a) =0

⇒ x+a = 0

⇒ x = -a. and y =b.

hope it helps!!!