bx and cy are perpendiculars to a line passing through the vertex a of triangle abc and z is the mid point of bc.prove that xz=yz
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From the diagram attached, since bx and cy are perpendiculars to a line passing through the vertex a, it follows that xy is parallel to bc
Again, from the diagram, bx = cy
Angle xbz = angle ycz = 90 degrees
Since z is the mid-point of bc, it follows that bz = zc
From the forgoing, triangle xbz is congruent to triangle ycz (SSS)
Therefore, xz=yz
Again, from the diagram, bx = cy
Angle xbz = angle ycz = 90 degrees
Since z is the mid-point of bc, it follows that bz = zc
From the forgoing, triangle xbz is congruent to triangle ycz (SSS)
Therefore, xz=yz
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Answered by
14
Step-by-step explanation:
c the attachment
hence proved that Xz = Yz
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