Question

by actual division find the remainder whenx^3-ax^2+6x-a is divided by x-a
pls tell fast!​

Answer 1

Answer:

5a

Step-by-step explanation:

We have, p(x)=x³−ax²+6x−a

Therefore, p(a)=a³−a³+6a−a

p(a)=5a

Thus, the required remainder is 5a.

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Answer 2

Answer:

x³-ax²+6x-a divided by x-a ee get reminder is 5a