By an engine, the consumption of coal is directly proportional to the square of its velocity. when velocity is 50 miles/ h coal consumption is 100 kg.if the cost of coal is 25p per kg and expenditure is 9 Rs./hour in the second case. Then find the consumption in travelling 250 miles.
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Answer:
Step-by-step explanation:
consumption ∝ velocity^2
thus consumption/velocity^2 = constant
when velocity = 50 mh^-1
consumption = 100kg
constant = 100/50^2 = 100/2500 = 1/25
cost = 25p/kg
expenditure = 9rs/hr
= 900p/hr
coal he using per hr = 900/25 = 36kg
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