By an engine the consumption of coal is directly proportional to the square of its velocity.when velocity is 50 mile/ h coal consumption is 100 kg.if the cost of coal is 25p per kgand expenditure is 9 Rs./hour in second case. Then find the consumption in travelling 250 mile.
Answers
Answered by
23
By an engine the consumption of coal is directly proportional to the square of its velocity.when velocity is 50 mile/ h coal consumption is 100 kg.if the cost of coal is 25p per kgand expenditure is 9 Rs./hour in second case. Then find the consumption in travelling 250 mile.
cost of coal= 25 p per kg
expense =9 rs/hr
coal consumed in 1 hr = 9/(25/100) = 36 kg
100 kg = c × 50^2
36 kg = c × velocity^2
c is constant
velocity^2/50^2 = 36/100
velocity /50 = 6/10
velocity = 30 miles per hour
time taken to travel 250 miles = 250/30
= 25/ 3 hr
consumption of coal = 36 × 25/3
= 300 kg
Answered by
0
Answer: 300kh
c is directly proportional to v1 ^2
C1/c2=k(v1/V2)^2 C1=100kg v1=50miles per hour c2=9*4=36
100/36=(50/V2)^2
V2=30
Time=250/30=25/3
Consumption=36*25/3=300kg
Step-by-step explanation:
c is directly proportional to v1 ^2
C1/c2=k(v1/V2)^2 C1=100kg v1=50miles per hour c2=9*4=36
100/36=(50/V2)^2
V2=30
Time=250/30=25/3
Consumption=36*25/3=300kg
Step-by-step explanation:
Similar questions