By applying a force of 1N one can hold a body whose mass is approximately equal to ?
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as F= mg
1 N = m×9.8
⇒ m= 1÷9.8
= 0.102 kg
1 N = m×9.8
⇒ m= 1÷9.8
= 0.102 kg
Answered by
0
M=102 gram.
Let F be the force in the body.
'm' be the mass of the body.
'a' is the acceleration
F=ma
Also the body is free fall
Acceleration=Gravity
A=G{9.8)
F=mg
m=F/g
M=1/9.8
M=0.102Kg
M=0.102× gram.
M=102 gram.
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