by complete squaring find 2x^2-7x+3
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2x^2-7x+3
2x^2-6x-x+3
2x (x-3)-1 (x-3)
(x-3)(2x-1)
2x^2-6x-x+3
2x (x-3)-1 (x-3)
(x-3)(2x-1)
sumbul23:
complete squaring.
Answered by
1
2x^2-7x+3 =0
= 2x^2-6x-x+3 =0
= 2x(x-3)-1(x-3)=0
= (x-3)(2x-1)=0
= x=3 or x=1/2
= 2x^2-6x-x+3 =0
= 2x(x-3)-1(x-3)=0
= (x-3)(2x-1)=0
= x=3 or x=1/2
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