by decreasing the radius of circle by 30% its area it decreased by how much percent
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answer is 49 % . please mark as the brainliest answer
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Let radius of circle be r.
Area of circle = pi.r^2
Radius decreases = 30%
New radius is r - 50%of r = 0.7 r
New area = 3.14 * (.7r)^2
= 0.49 * 3.14 * r^2
Hence decreasing in area = 51%
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