Question

by division process , find value of k for which x - 1 is a factor of x³ - 6x² + 11x + k .

please solve by divison process.....

thanku...

Answer 1

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Answer 2

Solution:-

Given:-

• Polynomial:- ( x³ - 6x² + 11x + k )
• ( x -1) is the Factor of the Polynomial.

To Find:-

• Value of k = ?

Find:-

∵ ( x -1) is the Factor of the given Polynomial.

=) x - 1 = 0

=) x = 1

P(x) = x³ - 6x² + 11x + k

=) P(1) = 1³ - 6(1)² + 11(1) + k

=) 0 = 1 - 6 + 11 + k

=) k = 6 - 11 - 1

=) k = -6

Hence,

• k takes the value of -6.