by elemination method solve:2x= 5y+4
3x-2y+16=0
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Answer:
(2x-5y=4)×3......1 equation
(3x-2y= -16) ×2......2 equation
2--1
6x-15y= 12
6x-4y= -32
signs changed and x cancel out
-11y=44
y= -4
2x-5(-4)=4
2x=4+20
x=24/2
x=12
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