- - - By how much does 3x3 - 5x2 + 2x - 3 exceed 2xc3 - 3x2 + x + 1? How much is - 2 + 7y2 - 3xy less than 2x2 - y2 + xy? -
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Step-by-step explanation:
= (3x3 - 5x2 + 2x -3) - (2x3 - 3x2 + x + 1)
= 3x3 - 5x2 + 2x -3 - 2x3 + 3x2 - x -4
= x3 - 2x2 + x -7
So, 3x3 - 5x2 + 2x -3 exceed 2x3 - 3x2 + x + 1 by (x3 - 2x2 + x -7).
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